Back to Exercise: Explain volume formulas

Exercises: Informal Arguments for Sphere Volume Using Cavalieri's Principle

Grade 10·22 problems·~35 min·Common Core Math - HS Geometry·standard·hsg-gmd-a-2
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A

Recall / Warm-Up

1

A cylinder has radius r=4r = 4 cm and height h=5h = 5 cm. What is its volume?

A.

80π80\pi cm³

B.

80π3\frac{80\pi}{3} cm³

C.

40π40\pi cm³

D.

160π160\pi cm³

2

A cone has radius r=3r = 3 cm and height h=6h = 6 cm. What is its volume?

A.

18π18\pi cm³

B.

54π54\pi cm³

C.

12π12\pi cm³

D.

6π6\pi cm³

3

A right triangle has legs a=5a = 5 and h=12h = 12. Which expression gives the length of the hypotenuse?

A.

25+144=13\sqrt{25 + 144} = 13

B.

5+12=175 + 12 = 17

C.

144−25=119\sqrt{144 - 25} = \sqrt{119}

D.

5×12=605 \times 12 = 60

B

Fluency Practice

1

Two solids each have height 8 cm. At every height hh between 0 and 8 cm, the cross-sectional area of Solid A equals the cross-sectional area of Solid B. By Cavalieri's principle, if Solid A has volume 320π320\pi cm³, what is the volume of Solid B in cm³?

2

A hemisphere of radius r=6r = 6 cm is compared to a cylinder-minus-cone solid, where both the cylinder and the cone have radius 6 cm and height 6 cm. What is the volume of the cylinder-minus-cone solid in terms of π\pi?

Hemisphere cross-section showing the right triangle formed by radius r = 5, height h = 3, and cross-sectional radius x
3

A hemisphere of radius r=5r = 5 cm is sliced horizontally at height h=3h = 3 cm above its flat base. Using the Pythagorean Theorem, find the cross-sectional area at that height. Express your answer in terms of π\pi.

4

For a hemisphere of radius rr, at height hh above the flat base, the cross-sectional radius xx satisfies   ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲   . So the cross-sectional area is Ahemisphere(h)=A_{\text{hemisphere}}(h) =   ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲   .

5

For the cylinder-minus-cone comparison solid (cylinder radius rr, height rr; cone apex at base, base radius rr at top), at height hh the cone's inner radius equals   ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲   . The annular cross-sectional area is Aannulus(h)=A_{\text{annulus}}(h) =   ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲   .

6

Using the hemisphere argument: a hemisphere of radius rr has the same volume as a cylinder-minus-cone (both with radius rr and height rr). Compute the hemisphere volume when r=3r = 3 cm. Express your answer in terms of π\pi.

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