Back to Solve quadratic equations — Problem 3 · Task Set 37

HSA.REI.B.4 Tutor Intake — Solving Quadratic Equations

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Grade 9·9 problems·~14 min·Common Core Math - HS Algebra·standard·hsa-rei-b-4

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Procedures

A student completes the square on $x^2 - 6x + 2 = 0$ , arriving at
$(x - 3)^2 = 7$ .

Which values of $x$ solve the original equation?

$x = 3 + 7 = 10$ or $x = 3 - 7 = -4$

$x = 3 + \sqrt{7}$ or $x = 3 - \sqrt{7}$

$x = \sqrt{3 + 7}$ or $x = \sqrt{3 - 7}$

$x = 3$ (the only solution)