Back to Exercise: Coulomb's Law

Exercises: Coulomb's Law

Work through each section in order. Use k=9×109k = 9 \times 10^9 N·m²/C² throughout. Show your work on all calculation problems.

Grade 11·20 problems·~35 min·OpenStax Physics (High School)·section·sec-18-2
Printable layout
A

Warm-Up: Prerequisite Review

These questions review concepts needed for this section.

1

Newton's Law of Gravitation is F=Gm1m2r2F = \frac{Gm_1 m_2}{r^2}. Which term in this formula plays the same role as the charges in Coulomb's Law?

A.

The constant GG

B.

The distance rr

C.

The masses m1m_1 and m2m_2

D.

The force FF

2

Two charges of the same sign are brought close together. What type of electric force acts between them?

A.

Attractive

B.

Repulsive

C.

No force — they cancel each other.

D.

It depends on which charge is larger.

3

Which feature do Coulomb's Law and Newton's Law of Gravitation share?

A.

Both forces can only be attractive.

B.

Both forces follow an inverse-square relationship with distance.

C.

Both use the same constant (k=Gk = G).

D.

Both forces are equal in magnitude for the same pair of objects.

B

Fluency Practice

Use k=9×109k = 9 \times 10^9 N·m²/C². Show your work and state the direction of each force.

1

Two protons are separated by a distance rr. Which of the following correctly describes the electric force between them?

A.

Attractive, with magnitude F=ke2r2F = \frac{k e^2}{r^2}

B.

Repulsive, with magnitude F=ke2r2F = \frac{k e^2}{r^2}

C.

Attractive, with magnitude F=ker2F = \frac{k e}{r^2}

D.

Zero — protons are too small to exert detectable forces.

2

Calculate the magnitude of the electric force between two charges: q1=+3×10−6q_1 = +3 \times 10^{-6} C and q2=+5×10−6q_2 = +5 \times 10^{-6} C, separated by r=0.30r = 0.30 m. Express your answer in newtons to two significant figures.

3

Calculate the magnitude of the electric force between q1=+2×10−6q_1 = +2 \times 10^{-6} C and q2=−4×10−6q_2 = -4 \times 10^{-6} C separated by r=0.20r = 0.20 m. Express your answer in newtons to two significant figures.

4

The electric force between two charges separated by distance rr is FF. If the distance is doubled to 2r2r (charges unchanged), what is the new force?

A.

F2\frac{F}{2} — distance doubled, force halved

B.

F4\frac{F}{4} — distance doubled, force reduced by factor of 4

C.

2F2F — force doubles when distance doubles

D.

4F4F — force quadruples when distance doubles

A number line showing three charges: A (+4 μC) at 0 m, B (−2 μC) at 0.30 m, and C (+3 μC) at 0.50 m
5

Three charges are on a line. Charge A (+4μ+4 \muC) is at position 0, charge B (−2μ-2 \muC) is at 0.30 m, and charge C (+3μ+3 \muC) is at 0.50 m. Find the net force on charge B.

Taking rightward as positive, what is the net force on B in newtons? (Positive = right, negative = left.) Express your answer to two significant figures.

6

In the same setup (A at 0, B at 0.30 m, C at 0.50 m), what is the net force on charge C? (Positive = right, negative = left.) Express your answer to two significant figures.

You're viewing 2 of 6 sections.

Create a free account to continue the full exercise set and save your progress.

Create free account