Back to Exercise: Use permutations and combinations to compute probabilities

Exercises: Use Permutations and Combinations to Compute Probabilities

Work through each section in order. Before computing a count, ask the
deciding question: "If I swap two of my chosen items, is it a DIFFERENT
outcome?" If yes, order matters — use a permutation, nPr = n!/(n - r)!.
If no, order does not matter — use a combination,
nCr = nPr / r! = n!/(r!(n - r)!). For probabilities, count the favorable
and the total the SAME way (both ordered or both unordered).

Grade 11·20 problems·~35 min·Common Core Math - HS Statistics and Probability·group·hss-cp-b-9
Printable layout
A

Warm-Up: Counting Principle, Factorials, and Order

These problems review the counting building blocks.

1.

A deli offers 3 kinds of bread and 5 kinds of filling. A sandwich is one bread and one filling. By the Fundamental Counting Principle, how many different sandwiches are possible?

A.

3×5=153 \times 5 = 15

B.

3+5=83 + 5 = 8

C.

53=25 - 3 = 2

D.

$3! = 6$

2.

Compute the factorial $5!$ ($5! = 5 \times 4 \times 3 \times 2 \times 1$).

3.

You choose 3 people from a group. In which situation does ORDER MATTER (so swapping two chosen people gives a different outcome)?

A.

Choosing a president, then a vice-president, then a treasurer.

B.

Choosing a 3-person committee with no titles.

C.

Choosing 3 people to all receive the same prize.

D.

Choosing 3 people to form a study group.

B

Fluency Practice

Compute each count. Cancel factorials before multiplying out.

1.

A 4-character password uses one digit (0-9) for each character, repeats allowed. By the counting principle, how many passwords are possible? (Enter the number.)

2.

Compute the permutation 8P3=8!(83)!=8!5!_8P_3 = \dfrac{8!}{(8-3)!} = \dfrac{8!}{5!}.

3.

Compute the combination 8C3=8P33!=8!3!(83)!_8C_3 = \dfrac{_8P_3}{3!} = \dfrac{8!}{3!\,(8-3)!}.

4.

A shelf will hold 4 of 7 distinct books arranged left to right. How many arrangements are possible? Compute 7P4_7P_4.

5.

How many different 3-topping pizzas can be made from 6 available toppings, if no topping is repeated and order does not matter? Compute 6C3_6C_3.

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