Back to Exercise: Understand independence via the product rule

Exercises: Understand Independence Through the Product Rule

Work through each section in order. For independence tests, compute P(A)P(A), P(B)P(B), and P(A and B)P(A \text{ and } B), then compare P(A and B)P(A \text{ and } B) to the product P(A)P(B)P(A) \cdot P(B). For explanation problems, write in complete sentences.

Grade 10·21 problems·~35 min·Common Core Math - HS Statistics and Probability·group·hss-cp-a-2
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A

Warm-Up: Probability Foundations

These problems review skills you already know.

1.

A fair coin is flipped twice. Listing the sample space {HH,HT,TH,TT}\{HH, HT, TH, TT\}, what is P(both heads)P(\text{both heads})? Express your answer as a fraction.

2.

Which statement about the word "independent" in probability is correct?

A.

Independence is a relationship between two events: AA is independent of BB.

B.

Independence is a property a single event has on its own.

C.

An event is independent whenever its probability is greater than 0.50.5.

D.

Independence only describes events from two separate experiments.

3.

Two events AA and BB are mutually exclusive when they cannot both occur. What is P(A and B)P(A \text{ and } B) for mutually exclusive events?

A.

P(A and B)=0P(A \text{ and } B) = 0

B.

P(A and B)=P(A)P(B)P(A \text{ and } B) = P(A) \cdot P(B)

C.

P(A and B)=P(A)+P(B)P(A \text{ and } B) = P(A) + P(B)

D.

P(A and B)=1P(A \text{ and } B) = 1

B

Fluency Practice

Test each pair of events using the product rule.

1.

Two fair coins are flipped. Let $A = $ "first coin is heads" and $B = $ "second coin is heads." Compute P(A)P(B)P(A) \cdot P(B). Express your answer as a fraction.

2.

A fair die is rolled once. Let $A = $ "even" ={2,4,6}= \{2, 4, 6\} and $B = $ "greater than 2" ={3,4,5,6}= \{3, 4, 5, 6\}. Compute P(A and B)P(A \text{ and } B) directly by counting the outcomes in both events. Express your answer as a fraction.

3.

Using the same die events, $A = $ "even" and $B = $ "greater than 2," we have P(A)=12P(A) = \frac{1}{2}, P(B)=23P(B) = \frac{2}{3}, and P(A and B)=13P(A \text{ and } B) = \frac{1}{3}. Are AA and BB independent?

A.

Yes — P(A)P(B)=1223=13=P(A and B)P(A) \cdot P(B) = \frac{1}{2} \cdot \frac{2}{3} = \frac{1}{3} = P(A \text{ and } B), so the product rule holds.

B.

No — the two events come from the same die, so they cannot be independent.

C.

No — P(A)P(B)=1223=2313P(A) \cdot P(B) = \frac{1}{2} \cdot \frac{2}{3} = \frac{2}{3} \neq \frac{1}{3}.

D.

Cannot tell without listing the full sample space again.

4.

A spinner lands on red with probability 0.40.4. It is spun twice, and the two spins are independent. What is the probability it lands on red both times? Give a decimal.

5.

You are told P(A)=0.5P(A) = 0.5, P(B)=0.4P(B) = 0.4, and P(A and B)=0.25P(A \text{ and } B) = 0.25. Are AA and BB independent?

A.

No — P(A)P(B)=0.200.25P(A) \cdot P(B) = 0.20 \neq 0.25, so the product rule fails and the events are dependent.

B.

Yes — both probabilities are positive, so the events must be independent.

C.

Yes — 0.250.25 is close enough to 0.200.20 that we call them independent.

D.

Cannot decide without knowing the experiment.

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