Back to Exercise: Prove theorems using similarity

Exercises: Prove Theorems Using Similarity

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Grade 9·21 problems·~35 min·Common Core Math - HS Geometry·standard·hsg-srt-b-4
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A

Warm-Up: Review What You Know

These problems review skills from previous lessons.

1

Two triangles share the same vertex angle AA. If a second pair of angles is also equal, which similarity criterion guarantees the triangles are similar?

2

Line DEDE is parallel to line BCBC, and line ABAB is a transversal crossing both.
Which statement correctly describes the relationship between ∠ADE\angle ADE and ∠ABC\angle ABC?

3

A right triangle has legs of length 5 and 12. What is the length of the hypotenuse?

B

Fluency Practice

Apply the Side-Splitter Theorem, its converse, or right-triangle similarity to find unknown values.

Triangle ABC with parallel segment DE. AD = 6, DB = 4, AE = 9, EC = ?.
1

In △ABC\triangle ABC, segment DE∥BCDE \parallel BC with DD on AB‾\overline{AB} and EE on AC‾\overline{AC}.
Given AD=6AD = 6, DB=4DB = 4, and AE=9AE = 9, find ECEC.

Triangle PQR with parallel segment ST. PS = 5, SQ = 3, PT = 7.5, TR = ?.
2

In △PQR\triangle PQR, segment ST∥QRST \parallel QR with SS on PQ‾\overline{PQ} and TT on PR‾\overline{PR}.
Given PS=5PS = 5, SQ=3SQ = 3, and PT=7.5PT = 7.5, find TRTR.

Triangle ABC with segment DE. AD = 8, DB = 4, AE = 10, EC = 5. Is DE parallel to BC?
3

In △ABC\triangle ABC, point DD lies on AB‾\overline{AB} and point EE lies on AC‾\overline{AC}.
Given AD=8AD = 8, DB=4DB = 4, AE=10AE = 10, and EC=5EC = 5. Is DE∥BCDE \parallel BC?

Right triangle ABC with altitude CD to hypotenuse AB. AD = 4, DB = 9, AC = ?.
4

Right triangle △ABC\triangle ABC has a right angle at CC. The altitude from CC meets
hypotenuse AB‾\overline{AB} at point DD, with AD=4AD = 4 and DB=9DB = 9.
Using the similarity of △ACD\triangle ACD and △ABC\triangle ABC, find ACAC.

Right triangle with altitude CD to hypotenuse. AD = 3, DB = 12, CD = h = ?.
5

In right △ABC\triangle ABC with right angle at CC, altitude CD‾\overline{CD} meets
hypotenuse AB‾\overline{AB} at DD with AD=3AD = 3 and DB=12DB = 12.
Using △ACD∼△CBD\triangle ACD \sim \triangle CBD, find the altitude length CDCD.

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