Back to Exercise: Prove theorems about parallelograms

Exercises: Prove Theorems About Parallelograms

Work through each section in order. Show all proof steps and justifications where indicated.

Grade 9·21 problems·~30 min·Common Core Math - HS Geometry·standard·hsg-co-c-11
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Warm-Up: Review What You Know

These problems review skills from earlier in the course that you will need for parallelogram proofs.

1

The midpoints of segment AC‾\overline{AC} and segment BD‾\overline{BD} are both the point (3,4)(3, 4). What can you conclude?

A.

AC‾\overline{AC} and BD‾\overline{BD} bisect each other.

B.

AC‾\overline{AC} and BD‾\overline{BD} are congruent.

C.

AC‾\overline{AC} and BD‾\overline{BD} are perpendicular.

D.

AC‾\overline{AC} and BD‾\overline{BD} are parallel.

2

Lines ℓ\ell and mm are parallel, and line tt is a transversal crossing both. Which statement about the alternate interior angles is true?

A.

They are supplementary (they sum to 180∘180^\circ).

B.

They are congruent.

C.

They are complementary (they sum to 90∘90^\circ).

D.

They are vertical angles.

3

In △ABC≅△DEF\triangle ABC \cong \triangle DEF, which reason justifies concluding that AB‾≅DE‾\overline{AB} \cong \overline{DE}?

A.

Definition of congruent triangles

B.

CPCTC (Corresponding Parts of Congruent Triangles are Congruent)

C.

SAS (Side-Angle-Side)

D.

Reflexive Property

B

Fluency Practice

Parallelogram ABCD with diagonal AC drawn as a dashed line from top-left vertex A to bottom-right vertex C.
1

Parallelogram ABCDABCD has diagonal AC‾\overline{AC} drawn. To prove △ABC≅△CDA\triangle ABC \cong \triangle CDA using ASA, a student uses the fact that AB∥DCAB \parallel DC. Which angle pair does this parallel relationship justify as congruent?

A.

∠BAC≅∠DCA\angle BAC \cong \angle DCA (alternate interior angles, transversal AC‾\overline{AC}, lines AB∥DCAB \parallel DC)

B.

∠ABC≅∠CDA\angle ABC \cong \angle CDA (corresponding angles, transversal AC‾\overline{AC}, lines AB∥DCAB \parallel DC)

C.

∠BAD≅∠BCD\angle BAD \cong \angle BCD (alternate interior angles, transversal AC‾\overline{AC}, lines AB∥DCAB \parallel DC)

D.

∠BAC≅∠DAC\angle BAC \cong \angle DAC (alternate interior angles, transversal AC‾\overline{AC}, lines AB∥DCAB \parallel DC)

2

In parallelogram ABCDABCD, it is given that AB=7AB = 7 cm and BC=4BC = 4 cm. What are the lengths of CDCD and DADA?

A.

CD=4CD = 4 cm, DA=7DA = 7 cm

B.

CD=7CD = 7 cm, DA=4DA = 4 cm

C.

CD=7CD = 7 cm, DA=7DA = 7 cm

D.

CD=4CD = 4 cm, DA=4DA = 4 cm

3

In parallelogram ABCDABCD, ∠A=65∘\angle A = 65^\circ. Find m∠Cm\angle C in degrees.

4

In parallelogram PQRSPQRS, ∠P=112∘\angle P = 112^\circ. Find m∠Qm\angle Q in degrees.

5

In quadrilateral WXYZWXYZ, the diagonals WY‾\overline{WY} and XZ‾\overline{XZ} intersect at point MM, with WM=MY=6WM = MY = 6 and XM=MZ=4XM = MZ = 4. Which conclusion is justified?

A.

WXYZWXYZ is a parallelogram because its diagonals bisect each other.

B.

WXYZWXYZ is a parallelogram because WY=XZWY = XZ.

C.

WXYZWXYZ is a parallelogram because one pair of opposite sides is congruent.

D.

WXYZWXYZ is a rectangle because the diagonals have different lengths.

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