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HSF.BF.B.4.d Tutor Intake — Domain Restriction and Invertible Functions

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Grade 9·10 problems·~14 min·Common Core Math - HS Functions·standard·hsf-bf-b-4d

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The function $f(x) = x^2 + 1$ is restricted to $x \geq 0$ .

After applying the swap-and-solve method, which expression is the
correct inverse $f^{-1}(x)$ ?

$f^{-1}(x) = -\sqrt{x - 1}$

$f^{-1}(x) = \sqrt{x + 1}$

$f^{-1}(x) = \sqrt{x - 1}$

$f^{-1}(x) = \sqrt{x} - 1$