Back to Solve linear-quadratic systems — Problem 2 · Task Set 44

Exercises: Solve Linear-Quadratic Systems

Show all algebraic steps. For each solution (x, y), verify in both original equations.

Grade 10·17 problems·~40 min·Common Core Math - HS Algebra·standard·hsa-rei-c-7

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Recall / Warm-Up

After substituting the linear equation into the quadratic in a linear-quadratic system, you get the equation $x^2 - 5x + 6 = 0$ . How many real solutions does this system have?

0, because the discriminant is negative

1, because this is a perfect square

2, because the discriminant is positive

Cannot be determined without the original equations