Back to Rearrange formulas — Problem 1 · Task Set 29

HSA.CED.A.4 Tutor Intake — Rearranging Formulas

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Grade 9·8 problems·~12 min·Common Core Math - HS Algebra·standard·hsa-ced-a-4

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Concepts

A student solves the equation $3x + 6 = 15$ by first subtracting 6
from both sides, then dividing both sides by 3, to get $x = 3$ .

The same student now needs to rearrange the formula $V = IR$ to find
$R$ . Which statement correctly describes the relationship between these
two tasks?

The formula requires a completely different approach because $V$ ,
$I$ , and $R$ are not numbers.

Rearranging $V = IR$ is the same type of move as solving $3x = 15$
— divide both sides by the coefficient of the target variable.

Formulas with three or more letters cannot be rearranged without
additional information about the values.

Only formulas with exactly one operation can be rearranged; $V = IR$
has multiplication, so it needs a different method.