Back to Solve real-world and mathematical problems leading to two linear equations in two variables — Problem 1 · Task Set 40

8.EE.C.8.c Tutor Intake -- Real-World Systems of Equations

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Grade 8·8 problems·~9 min·Common Core Math - Grade 8·standard·8-ee-c-8c

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Procedures

A rectangle's perimeter is 46 cm. Its length is 5 cm more than
twice its width: $l = 2w + 5$ . Using the perimeter equation
$2l + 2w = 46$ , substitute for $l$ and solve for the width $w$ .