Back to Exercise: Explain sine and cosine relationship

Exercises: Sine and Cosine of Complementary Angles

Grade 9·20 problems·~28 min·Common Core Math - HS Geometry·standard·hsg-srt-c-7
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A

Warm-Up

1.

Two angles are complementary. One angle measures 35°. What is the measure of the other angle?

2.

In a right triangle with acute angles α\alpha and β\beta, which statement must be true?

3.

In a right triangle with legs of length 3 and 4 and hypotenuse of length 5, if θ\theta is the angle opposite the side of length 3, then sin(θ)=oppositehypotenuse=000000000000\sin(\theta) = \dfrac{\text{opposite}}{\text{hypotenuse}} = \dfrac{\hspace{0.2em}\fbox{\phantom{000000}}\hspace{0.2em}}{\hspace{0.2em}\fbox{\phantom{000000}}\hspace{0.2em}} and cos(θ)=adjacenthypotenuse=000000000000\cos(\theta) = \dfrac{\text{adjacent}}{\text{hypotenuse}} = \dfrac{\hspace{0.2em}\fbox{\phantom{000000}}\hspace{0.2em}}{\hspace{0.2em}\fbox{\phantom{000000}}\hspace{0.2em}}.

opposite side:
hypotenuse for sin:
adjacent side:
hypotenuse for cos:
B

Fluency Practice

Right triangle ABC with right angle at C, angle A labeled 47 degrees, and angle B unknown
1.

In right triangle ABCABC with right angle at CC, if A=47°\angle A = 47\degree, then B=°\angle B = \underline{\hspace{5em}}\degree. The two acute angles are   ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲   angles.

measure of angle B:
relationship type:
2.

Which equation correctly states the complementary angle relationship for sine and cosine?

3.

Given that sin(32°)0.53\sin(32\degree) \approx 0.53, use the complementary angle relationship to find cos(58°)\cos(58\degree) without a calculator. cos(58°)=sin(°)\cos(58\degree) = \sin(\underline{\hspace{5em}}\degree) \approx \underline{\hspace{5em}}.

complementary angle:
value:
4.

Given that cos(71°)0.326\cos(71\degree) \approx 0.326, find sin(19°)\sin(19\degree) without a calculator. sin(19°)=cos(°)\sin(19\degree) = \cos(\underline{\hspace{5em}}\degree) \approx \underline{\hspace{5em}}.

complementary angle:
value:
5.

Simplify cos(90°x)\cos(90\degree - x). Your answer should be a single trig function of xx: cos(90°x)=\cos(90\degree - x) = \underline{\hspace{5em}}.

simplified expression:

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