Back to Explain sine and cosine relationship — Problem 3 · Task Set 20

Exercises: Sine and Cosine of Complementary Angles

Grade 9·20 problems·~28 min·Common Core Math - HS Geometry·standard·hsg-srt-c-7
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A

Warm-Up

1.

In a right triangle with legs of length 3 and 4 and hypotenuse of length 5, if θ\theta is the angle opposite the side of length 3, then sin(θ)=oppositehypotenuse=000000000000\sin(\theta) = \dfrac{\text{opposite}}{\text{hypotenuse}} = \dfrac{\hspace{0.2em}\fbox{\phantom{000000}}\hspace{0.2em}}{\hspace{0.2em}\fbox{\phantom{000000}}\hspace{0.2em}} and cos(θ)=adjacenthypotenuse=000000000000\cos(\theta) = \dfrac{\text{adjacent}}{\text{hypotenuse}} = \dfrac{\hspace{0.2em}\fbox{\phantom{000000}}\hspace{0.2em}}{\hspace{0.2em}\fbox{\phantom{000000}}\hspace{0.2em}}.

opposite side:
hypotenuse for sin:
adjacent side:
hypotenuse for cos: