Stage 2: Form the System
Decision variables:
Constraints:
(batches delivered) (hours available) ,
Objective: minimize
Stage 3: Graph the Feasible Region
: shade above (≥ means feasible side is above) : shade below (≤ means feasible side is below)
Mixed Constraint Directions: Test-Point Still Works
The system has one ≥ and one ≤ constraint:
: feasible region is above the line : feasible region is below the line
Test-point method works identically — the sign determines which side.
Stage 4: Find Corner Candidates
Check all axis candidates against both constraints:
- (8, 0): C1 pass, C2 pass → feasible
- (9, 0): C1 pass, C2 pass → feasible
- (0, 8): C1 pass, C2 fail → infeasible
- (0, 6): C1 fail, C2 pass → infeasible
Two Infeasible Candidates: Why They Fail
- (0, 8): 24 hours exceeds the 18-hour limit — fail
- (0, 6): only 6 batches, minimum is 8 — fail
Corner list: (6, 2), (8, 0), (9, 0)
Verify every candidate against all constraints.
Interior Corner: Calculating (6, 2)
Solve
Interior corner: (6, 2) ✓
Stage 5: Evaluation Table and Minimum
| Corner | C = 3x + 5y | Value |
|---|---|---|
| (6, 2) | 18 + 10 | 28 |
| (8, 0) | 24 + 0 | 24 |
| (9, 0) | 27 + 0 | 27 |
Minimum: C = 24 at (8, 0).
Check-In: Write the Interpreted Answer
Minimum
Write the full sentence:
"The delivery service should use ___ minivans and ___ lorries for a minimum cost of ___ UGX, delivering ___ batches within ___ hours."
The Surprise: No Lorries Is Cheapest
Minimum at
Why does using lorries increase cost?
- Minivans: 3,000 UGX per batch delivered
- Lorries: 5,000 UGX per batch delivered
Lorries carry more hours per trip — they cost more per trip too.
Bounded vs. Unbounded Feasible Regions
Two types of feasible regions:
- Bounded: enclosed polygon — has a finite maximum AND minimum
- Unbounded: open in one direction — minimum may exist; maximum may not
The carpenter region (LP-03) was bounded; today's transport region is also bounded.
Bounded vs. Unbounded: Two Regions Compared
- Bounded (left): every objective has both a max and a min
- Unbounded (right): min typically exists at a corner; max may be infinite
On Unbounded Regions: What Still Works
For an unbounded feasible region:
- Minimization: the minimum usually exists at a corner
- Maximization: the maximum may not exist — check for boundedness first
Safe rule: if only ≥ constraints appear, the region is likely unbounded.
Cafeteria Worked Example: Fractional Corner Alert
Minimize
- (7.5, 4.5):
3750 ← minimum - (30, 0):
- (0, 12):
Algebraically correct — but can you serve 7.5 cups? See LP-08.
Variant: What If Minivan Cost Rises?
Now both vehicles cost 5,000 UGX (equal):
- (6, 2):
- (8, 0):
- (9, 0):
Two corners tie — the optimum shifts when cost rates equalise.
Three Mistakes That Cost Marks
Watch out:
- Default to largest in minimization — state direction first; scan for smallest
- Treat minimization as a different method — same 5 stages; only the scan rule changes
- Accept fractional answers for integer variables — flag and apply LP-08
Check-In: Apply All Five Stages
Scenario: A farmer minimizes fertiliser cost. Corner list: (4, 2), (6, 0), (0, 5).
Objective: minimize
State direction. Build the table. Write the interpreted answer.
The Direction-Stating Habit Is Mandatory
Every LP problem from LP-06 onward must start:
"I am minimizing/maximizing [quantity]."
Write it. Every time. Before any algebra.
This sentence costs four seconds and prevents the most common LP error.
Key Takeaway: Same Method, Pick Smallest
✓ Recognize minimization from wording: cost, time, fuel, waste
✓ Same five stages as LP-05 — nothing new procedurally
✓ Evaluation table: scan for smallest value, not largest
✓ Write the direction before evaluating — every time
Coming Up: Lesson 7 — Maximum Profit
You can now solve LP problems in both directions.
Lesson 7 — Maximum Profit Problems:
- Fresh context: poultry farming
- Maximize revenue with an unbounded region
- Learn the diagnostic rule for unbounded max
Click to begin the narrated lesson
Minimum Cost Problems