Minimum Cost Problems | Lesson 6 of 10

Minimum Cost Problems

Lesson 6 of 10

In this lesson:

  • Recognise minimization contexts from wording
  • Apply the five-stage method to minimize cost
  • State the direction before every evaluation
Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

What You Will Learn Today

By the end of this lesson, you should be able to:

  1. Recognise minimization contexts from key wording cues
  2. Apply all five stages to a minimum cost problem
  3. State the optimization direction before evaluating
Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Hook: From Profit to Minimizing Cost

In LP-05, the carpenter maximized profit:

"Make 5 tables and 0 chairs for maximum profit of 100."

Today a delivery manager minimizes cost:

"Which vehicle mix delivers the batches most cheaply?"

Same method. Opposite direction.

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Wording-Sort: Identify the Optimization Direction

Sort these five cues: profit · cost · revenue · fuel use · time

  • Which cues mean "find more"?
  • Which cues mean "find less"?

Sort before the next slide reveals the rule.

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Wording-to-Direction Rule for LP Problems

Wording cue Direction
profit, revenue, output, yield Maximize
cost, expense, time, fuel, waste Minimize

Write the direction before any algebra.

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

The Direction-Stating Habit Prevents Errors

Before any algebra, write:

"I am minimizing cost C."

This 4-second commitment prevents the most common LP-06 error:

  • Wrong: scanning for the largest value in a minimization table
  • Right: scanning for the smallest value
Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Check-In: State the Direction and Quantity

Scenario: A hospital administrator wants to reduce daily drug waste.

Write the direction statement and name the quantity.

Pause and write before advancing.

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Stage 1: Read the Transport Scenario

Context: A delivery service transports maize sacks.

  • Minivans : 1 batch/trip, 2 h/trip, 3,000 UGX/trip
  • Lorries : 1 batch/trip, 3 h/trip, 5,000 UGX/trip
  • At least 8 batches needed; max 18 hours available

Direction: minimize total cost.

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Stage 2: Form the System

Decision variables: = minivans, = lorries

Constraints:

  • (batches delivered)
  • (hours available)
  • ,

Objective: minimize (thousands UGX)

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Stage 3: Graph the Feasible Region

Transport feasible region with x+y≥8 and 2x+3y≤18 shaded; corners (6,2), (8,0), (9,0) marked; (0,6) and (0,8) shown as infeasible

  • : shade above (≥ means feasible side is above)
  • : shade below (≤ means feasible side is below)
Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Mixed Constraint Directions: Test-Point Still Works

The system has one ≥ and one ≤ constraint:

  • : feasible region is above the line
  • : feasible region is below the line

Test-point method works identically — the sign determines which side.

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Stage 4: Find Corner Candidates

Check all axis candidates against both constraints:

  • (8, 0): C1 pass, C2 pass → feasible
  • (9, 0): C1 pass, C2 pass → feasible
  • (0, 8): C1 pass, C2 fail → infeasible
  • (0, 6): C1 fail, C2 pass → infeasible
Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Two Infeasible Candidates: Why They Fail

  • (0, 8): 24 hours exceeds the 18-hour limit — fail
  • (0, 6): only 6 batches, minimum is 8 — fail

Corner list: (6, 2), (8, 0), (9, 0)

Verify every candidate against all constraints.

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Interior Corner: Calculating (6, 2)

Solve and simultaneously:

Interior corner: (6, 2)

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Stage 5: Evaluation Table and Minimum

Transport evaluation table with C=3x+5y at (6,2)=28, (8,0)=24, (9,0)=27; minimum highlighted at (8,0)

Corner C = 3x + 5y Value
(6, 2) 18 + 10 28
(8, 0) 24 + 0 24
(9, 0) 27 + 0 27

Minimum: C = 24 at (8, 0).

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Check-In: Write the Interpreted Answer

Minimum at — in thousands UGX.

Write the full sentence:

"The delivery service should use ___ minivans and ___ lorries for a minimum cost of ___ UGX, delivering ___ batches within ___ hours."

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

The Surprise: No Lorries Is Cheapest

Minimum at eight minivans, zero lorries.

Why does using lorries increase cost?

  • Minivans: 3,000 UGX per batch delivered
  • Lorries: 5,000 UGX per batch delivered

Lorries carry more hours per trip — they cost more per trip too.

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Bounded vs. Unbounded Feasible Regions

Two types of feasible regions:

  • Bounded: enclosed polygon — has a finite maximum AND minimum
  • Unbounded: open in one direction — minimum may exist; maximum may not

The carpenter region (LP-03) was bounded; today's transport region is also bounded.

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Bounded vs. Unbounded: Two Regions Compared

Left: closed carpenter polygon labelled "bounded — max and min both exist." Right: open cafeteria region extending upper-right, labelled "unbounded — min exists; max may not"

  • Bounded (left): every objective has both a max and a min
  • Unbounded (right): min typically exists at a corner; max may be infinite
Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

On Unbounded Regions: What Still Works

For an unbounded feasible region:

  • Minimization: the minimum usually exists at a corner
  • Maximization: the maximum may not exist — check for boundedness first

Safe rule: if only ≥ constraints appear, the region is likely unbounded.

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Cafeteria Worked Example: Fractional Corner Alert

Minimize . Corners: (7.5, 4.5), (30, 0), (0, 12)

  • (7.5, 4.5): 3750 ← minimum
  • (30, 0):
  • (0, 12):

Algebraically correct — but can you serve 7.5 cups? See LP-08.

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Variant: What If Minivan Cost Rises?

Now both vehicles cost 5,000 UGX (equal):

  • (6, 2):
  • (8, 0):
  • (9, 0):

Two corners tie — the optimum shifts when cost rates equalise.

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Three Mistakes That Cost Marks

⚠️ Watch out:

  • Default to largest in minimization — state direction first; scan for smallest
  • Treat minimization as a different method — same 5 stages; only the scan rule changes
  • Accept fractional answers for integer variables — flag and apply LP-08
Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Check-In: Apply All Five Stages

Scenario: A farmer minimizes fertiliser cost. Corner list: (4, 2), (6, 0), (0, 5).

Objective: minimize .

State direction. Build the table. Write the interpreted answer.

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

The Direction-Stating Habit Is Mandatory

Every LP problem from LP-06 onward must start:

"I am minimizing/maximizing [quantity]."

Write it. Every time. Before any algebra.

This sentence costs four seconds and prevents the most common LP error.

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Key Takeaway: Same Method, Pick Smallest

✓ Recognize minimization from wording: cost, time, fuel, waste

✓ Same five stages as LP-05 — nothing new procedurally

✓ Evaluation table: scan for smallest value, not largest

✓ Write the direction before evaluating — every time

Grade 10 Mathematics | S4 Topic 3: Linear Programming
Minimum Cost Problems | Lesson 6 of 10

Coming Up: Lesson 7 — Maximum Profit

You can now solve LP problems in both directions.

Lesson 7 — Maximum Profit Problems:

  • Fresh context: poultry farming
  • Maximize revenue with an unbounded region
  • Learn the diagnostic rule for unbounded max
Grade 10 Mathematics | S4 Topic 3: Linear Programming

Click to begin the narrated lesson

Minimum Cost Problems