Back to Exercise: Ohm's Law

Exercises: Ohm's Law

Work through each section in order. Show your work for all calculation problems.

Grade 11·20 problems·~30 min·OpenStax Physics (High School)·section·sec-19-1
Work through problems with immediate feedback
A

Recall / Warm-Up

1.

Electric current II is defined as:

2.

Conventional current in a circuit flows in which direction?

3.

Which statement about electrical resistance is correct?

B

Fluency Practice

1.

A charge of ΔQ=15 C\Delta Q = 15\ \text{C} flows through a wire in Δt=5.0 s\Delta t = 5.0\ \text{s}. What is the current in the wire?

2.

A 9.0 V battery is connected to a resistor of R=150 ΩR = 150\ \Omega. What current flows through the resistor?

3.

A current of I=2.5 AI = 2.5\ \text{A} flows through a resistor, and the voltage across it is V=15 VV = 15\ \text{V}. What is the resistance of the resistor?

4.

A resistor has R=20 ΩR = 20\ \Omega and carries a current of I=0.50 AI = 0.50\ \text{A}. What voltage appears across it?

C

Mixed Practice

1.

A circuit has one resistor connected to a 12 V battery. The resistor has 12 V across it. Another resistor is added to the circuit (in series). What happens to the voltage across the first resistor?

2.

A V-I measurement for an unknown resistor gives: at V=6.0 VV = 6.0\ \text{V}, the current is I=0.030 AI = 0.030\ \text{A}. What is the resistance of the resistor in ohms?

3.

A copper wire is replaced with a wire of the same material but twice the length and half the cross-sectional area. By what factor does the resistance change?

V-I graph showing a straight line through the origin, indicating an ohmic device.
4.

A V-I graph for a device shows a straight line through the origin. What can you conclude about this device?

5.

On a V-I graph, a light bulb filament shows a curve that bends away from the straight-line ohmic behavior — the slope of the curve decreases at higher voltages. What does this tell you about the filament's resistance?

D

Word Problems

1.

A phone charging cable carries a current of I=1.5 AI = 1.5\ \text{A} for Δt=45 min\Delta t = 45\ \text{min}.

How much charge (in coulombs) flows through the cable during this time?

2.

A heating element in a toaster has resistance R=24 ΩR = 24\ \Omega and is connected to a household outlet supplying V=120 VV = 120\ \text{V}.

1.

What current flows through the heating element?

2.

If the resistance of the heating element increases to R=30 ΩR' = 30\ \Omega after it heats up (due to increased temperature), what is the new current?

E

Error Analysis

1.

Student's explanation:

"In a circuit with a battery and two resistors in series, the voltage starts at 12 V at the battery. The first resistor uses up some of the voltage, say 5 V worth. The second resistor uses up the remaining 7 V. By the time current gets back to the battery, the voltage has been used up completely — that's why the battery has to keep making more voltage."

A student describes how voltage works in a circuit. Read their explanation and identify the error.

2.

Student's reasoning:

"I replaced the 20 Ω20\ \Omega resistor with a 100 Ω100\ \Omega resistor in the same circuit (same 12 V battery). Since resistance drives current, the larger resistance will push more current through the circuit. I calculate the new current as I=R×V=100×12=1200 AI = R \times V = 100 \times 12 = 1200\ \text{A}."

A student analyzes a circuit and makes a claim. Read their reasoning and find the mistake.

F

Challenge

1.

Explain in physical terms (using the electron-collision model) why the resistance of a metal wire increases when its temperature increases, but the resistance of a thermistor (semiconductor) decreases when its temperature increases. What does this tell you about the different physical mechanisms in metals vs. semiconductors?

2.

A V-I graph for a non-ohmic device shows the following data points: at V=2 VV = 2\ \text{V}, I=0.10 AI = 0.10\ \text{A}; at V=6 VV = 6\ \text{V}, I=0.20 AI = 0.20\ \text{A}.

1.

Calculate the resistance at each operating point. At V=2 VV = 2\ \text{V}: R=R =   ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲   Ω\Omega. At V=6 VV = 6\ \text{V}: R=R =   ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲   Ω\Omega.

R at V=2V (Ω):
R at V=6V (Ω):
2.

The two resistance values you calculated are different. What does this change in resistance tell you about the device? What physical process could explain the increase in resistance at higher current?

0 of 20 answered