"Speed is the rate at which an object changes its location. Like distance, speed is a scalar because it has a magnitude but not a direction."
"$\Delta t = t_f - t_0.$"
"Average speed, *v*_avg, is the distance traveled divided by the time during which the motion occurs."
"Its speed at a specific instant in time, however, is its instantaneous speed. A car's speedometer describes its instantaneous speed."
"Velocity describes the speed and direction of an object. ... Average velocity is displacement divided by the time over which the displacement occurs."
"$\vec{v}_{\text{avg}} = \frac{\text{displacement}}{\text{time}} = \frac{\Delta\vec{d}}{\Delta t} = \frac{\vec{d}_f - \vec{d}_0}{t_f - t_0}$"
"If your car's odometer shows the total distance traveled was 6 km, then your average speed was 12 km/h. Your average velocity, however, was zero because your displacement for the round trip is zero."
"A student has a displacement of 304 m north in 180 s. ... $\vec{v}_{\text{avg}} = \frac{\Delta\vec{d}}{\Delta t} = \frac{304 \text{ m}}{180 \text{ s}} = 1.7 \text{ m/s north}$"
"Layla jogs with an average velocity of 2.4 m/s east. ... $\Delta\vec{d} = \vec{v}_{\text{avg}} \, \Delta t = (2.4 \text{ m/s})(46 \text{ s}) = 1.1 \times 10^2 \text{ m east}$"
"Phillip walks ... 428 m west with an average velocity of 1.7 m/s west? ... $\Delta t = \frac{\Delta\vec{d}}{\vec{v}_{\text{avg}}} = \frac{428 \text{ m}}{1.7 \text{ m/s}} = 2.5 \times 10^2 \text{ s}$"
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"Speed is the rate at which an object changes its location. Like distance, speed is a scalar because it has a magnitude but not a direction."
"$\Delta t = t_f - t_0.$"
"Average speed, vavg, is the distance traveled divided by the time during which the motion occurs."
"Its speed at a specific instant in time, however, is its instantaneous speed. A car's speedometer describes its instantaneous speed."
"Velocity describes the speed and direction of an object. ... Average velocity is displacement divided by the time over which the displacement occurs."
"$\vec{v}{\text{avg}} = \frac{\text{displacement}}{\text{time}} = \frac{\Delta\vec{d}}{\Delta t} = \frac{\vec{d}f - \vec{d}0}{t_f - t_0}$"
"If your car's odometer shows the total distance traveled was 6 km, then your average speed was 12 km/h. Your average velocity, however, was zero because your displacement for the round trip is zero."
"A student has a displacement of 304 m north in 180 s. ... $\vec{v}{\text{avg}} = \frac{\Delta\vec{d}}{\Delta t} = \frac{304 \text{ m}}{180 \text{ s}} = 1.7 \text{ m/s north}$"
"Layla jogs with an average velocity of 2.4 m/s east. ... $\Delta\vec{d} = \vec{v}{\text{avg}} , \Delta t = (2.4 \text{ m/s})(46 \text{ s}) = 1.1 \times 10^2 \text{ m east}$"
"Phillip walks ... 428 m west with an average velocity of 1.7 m/s west? ... $\Delta t = \frac{\Delta\vec{d}}{\vec{v}_{\text{avg}}} = \frac{428 \text{ m}}{1.7 \text{ m/s}} = 2.5 \times 10^2 \text{ s}$"
What you'll learn
- Calculate the average speed of an object as distance/time, and rearrange the relation to solve for distance or time
- Distinguish instantaneous speed from average speed
- Calculate average velocity from displacement and time using v_avg = Δd/Δt
- Distinguish speed (a scalar) from velocity (a vector), and explain why the magnitude of average velocity is not generally equal to average speed
- Distinguish instantaneous velocity from average velocity
Prerequisites
Slides
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