Try Various, But Reasonable, Chances
The standard asks you to try different reasonable odds — not just one.
The better policy is a function of the accident probability, not a fixed verdict.
Recompute for a Higher-Risk Driver
At accident probability
Write Each Cost as a Function of p
Let
Set the Two Costs Equal
The break-even
Solve for the Break-Even Probability
Report a Condition, Not a Verdict
The complete answer:
Choose Policy B if your accident probability is below about 0.53; otherwise choose Policy A.
Your Turn: A Warranty Break-Even
A phone repair costs $600. A warranty costs $90 up front and covers it.
Find the repair probability
Set warranty cost = expected self-insure cost.
But Expected Cost Isn't the Whole Story
We've been minimizing expected cost.
Yet people rationally buy insurance that costs more on average. Why?
Insurance Costs More — and Is Still Rational
Buying insurance has a higher expected cost than self-insuring.
You pay a small certain amount to cap a rare, ruinous loss.
Same Average, Very Different Worst Case
Two strategies can share a mean but differ wildly in their worst outcome.
Risk Can Override the Average
- Expected cost is the primary decision criterion
- But the size of possible losses — risk — also matters
- A risk-averse person may accept a higher average to cap the worst case
Your Turn: When Does Risk Win?
A business can take a steady plan or a risky plan with the same expected profit, but the risky one has a small chance of bankruptcy.
Which should a small, cash-poor company choose — and why?
What You Built In This Lesson
✓ Recompute under new odds; find the break-even probability
✓ Report a condition, not a single verdict
✓ Expected cost is primary — but risk can override it
Coming Up Next: Full Decision Analysis
The next standard adds conditional probability and asymmetric error costs to the frame.
You'll analyze medical tests, product testing, and a coach pulling the goalie.
Click to begin the narrated lesson
Evaluate and compare strategies using expected values