HSF.TF.C.9 Tutor Intake — Angle Addition and Double Angle Formulas

$\sin(A + B) = \sin A + \sin B$

$\sin(A + B) = \sin A \cos B + \cos A \sin B$

$\sin(A + B) = \sin A \cos B - \cos A \sin B$

$\sin(A + B) = \cos A \cos B - \sin A \sin B$

$\cos(A + B) = \cos A \cos B + \sin A \sin B$

$\cos(A + B) = \cos A \cos B - \sin A \sin B$

$\cos(A + B) = \cos A + \cos B$

$\cos(A + B) = \sin A \cos B + \cos A \sin B$

A completely new identity that must be memorized independently

The addition formula for $\sin(A + B)$ with $B$ replaced by $A$

A consequence of the Pythagorean identity only

A definition of $\sin(2A)$ with no connection to $\sin(A + B)$

$\tan(A + B) = \tan A + \tan B$

$\tan(A + B) = \dfrac{\tan A - \tan B}{1 + \tan A \tan B}$

$\tan(A + B) = \dfrac{\tan A + \tan B}{1 - \tan A \tan B}$

$\tan(A + B) = \tan A \cdot \tan B$

$\dfrac{\sqrt{6} - \sqrt{2}}{4}$

$\dfrac{\sqrt{6} + \sqrt{2}}{4}$

$\dfrac{\sqrt{3} + 1}{4}$

$\dfrac{\sqrt{2} + \sqrt{3}}{2}$

$\dfrac{\sqrt{6} + \sqrt{2}}{4}$

$\dfrac{\sqrt{6} - \sqrt{2}}{4}$

$\dfrac{\sqrt{3} - 1}{4}$

$\dfrac{\sqrt{2} - \sqrt{6}}{4}$

$\dfrac{9}{25}$

$\dfrac{6}{5}$

$\dfrac{24}{25}$

$\dfrac{3}{5}$

$2\cos^2 A - 1$

$1 - 2\cos^2 A$

$2\sin A \cos A$

$\cos^2 A + \sin^2 A$