Back to Tutor Intake Assessment: Prove and use Pythagorean identity

HSF.TF.C.8 Tutor Intake — Pythagorean Identity and Trig Values

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Grade 9·10 problems·~13 min·Common Core Math - HS Functions·group·hsf-tf-c-8
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A

Concepts

1.

The Pythagorean identity sin2(θ)+cos2(θ)=1\sin^2(\theta) + \cos^2(\theta) = 1 can be proved by
starting with which equation?

2.

The Pythagorean identity sin2(θ)+cos2(θ)=1\sin^2(\theta) + \cos^2(\theta) = 1 holds for
  ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲   [scope]  ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲ ̲   values of θ\theta.

scope:
3.

A student applies the Pythagorean identity and finds sin2(θ)=925\sin^2(\theta) = \dfrac{9}{25}.
The student writes sin(θ)=35\sin(\theta) = \dfrac{3}{5} as the final answer. What is wrong
with this reasoning?

B

Procedures

1.

Given cos(θ)=35\cos(\theta) = \dfrac{3}{5} and θ\theta is in Quadrant I, use the
Pythagorean identity to find sin(θ)\sin(\theta). Enter your answer as a fraction
(e.g., 4/5).

2.

Given sin(θ)=513\sin(\theta) = -\dfrac{5}{13} and θ\theta is in Quadrant III, use the
Pythagorean identity to find cos(θ)\cos(\theta). Enter your answer as a fraction
(e.g., -12/13).

3.

If cos(θ)=23\cos(\theta) = -\dfrac{2}{3} and θ\theta is in Quadrant II, what is
sin(θ)\sin(\theta)?

4.

Given sin(θ)=513\sin(\theta) = \dfrac{5}{13} and θ\theta is in Quadrant II, find
tan(θ)\tan(\theta). Enter your answer as a fraction (e.g., -5/12).

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