Back to Exercise: Derive geometric series formula

Exercises: Geometric Series Formula

For each problem, identify the parameters a, r, and n before applying any formula. Always check whether r = 1. Show your work for computation problems.

Grade 9·22 problems·~45 min·Common Core Math - HS Algebra·standard·hsa-sse-b-4
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A

Recall / Warm-Up

1.

The sequence 3,6,12,24,483, 6, 12, 24, 48 is geometric. What is the common ratio rr?

2.

What is the 4th term of the geometric sequence with first term a=5a = 5 and common ratio r=3r = 3?

3.

What is the difference between the 5th term and the sum of the first 5 terms of the sequence 2,6,18,54,1622, 6, 18, 54, 162?

B

Fluency Practice

1.

Find the sum of the geometric series 3+6+12+24+48+963 + 6 + 12 + 24 + 48 + 96.

Use the formula S=a(rn1)r1S = \dfrac{a(r^n - 1)}{r - 1}.

2.

Find the sum of the geometric series 80+40+20+10+580 + 40 + 20 + 10 + 5.

Use the formula S=a(1rn)1rS = \dfrac{a(1 - r^n)}{1 - r}.

3.

Find the sum of the geometric series 1+3+9+27+81+2431 + 3 + 9 + 27 + 81 + 243.

Use the formula S=a(rn1)r1S = \dfrac{a(r^n - 1)}{r - 1}.

4.

What is the sum of the geometric series 7+7+7+7+7+77 + 7 + 7 + 7 + 7 + 7 (six terms)?

5.

For the geometric series with a=4a = 4, r=12r = \frac{1}{2}, n=8n = 8, which formula form is most convenient to use?

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