Bridge: Completing the Square with Letters
Last lesson:
Today: replace 6 with
What if we ran the same five steps with letters instead of numbers?
Derivation Step 1: Divide by
Start:
Divide everything by
Move the constant:
Derivation Step 2: Complete the Square
Half of
Derivation Step 3: Arrive at the Formula
From
The quadratic formula — completing the square, done once for all.
Applying the Quadratic Formula Correctly
- Label
, , before substituting - Compute
first - Simplify both the
and cases
Works for every
Apply the Formula: Integer Solutions
Solve:
Verify:
Apply the Formula: Irrational Solutions
Solve:
Does this factor over the integers? No — use the formula.
Check-In: Identify , , and the Discriminant
For
- Write
- Compute
- How many real solutions does this equation have?
Solve completely.
Using the Discriminant to Classify Solutions
Why Factor When the Formula Works?
The formula always works — so why use any other method?
| Equation | Fastest approach |
|---|---|
| Inspection: |
|
| Factor: |
|
| Formula: no integer factors | |
| Formula: discriminant |
The formula is a reliable backup, not the first choice.
Choose a Method and Solve
Choose the method and solve:
For each: name the method, execute, state the solution set.
When the Discriminant Is Negative
Define:
Complex solutions use
Complex Solutions in Form
Solve:
Solutions:
Complex Solutions Come in Conjugate Pairs
If
Verify
Guided Practice: Solving with Complex Results
Solve:
Step 1:
Step 2: $b^2 - 4ac = $ ____
Step 3:
Step 4: $x = $ ____ in
Discriminant Detective: Predict Then Solve
Compute
Discriminant first — then solve.
Full Process from Blank Slate
No hints. Choose your method and solve completely.
For each: state solution type, show work, write solution set.
What You Can Do Now
✓ Derive the quadratic formula from completing the square
✓ Label
✓ Choose the fastest method for each equation
Label
Negative discriminant → complex solutions, not "no solution"
Coming Up: Solving Linear-Quadratic Systems
Next: HSA.REI.C.7 — what happens when a linear and a quadratic equation are both true at once?
The intersection points of a line and a parabola satisfy both equations.
Solving those systems uses the quadratic-solving skills you have now.