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Remainder Theorem | Lesson 2 of 7: HSA.APR

The Remainder Theorem

Lesson 2 of 7: Arithmetic with Polynomials

In this lesson:

  • Discover that remainder = p(a) when dividing by (x − a)
  • Use the Factor Theorem to find factors from zeros
  • Use synthetic division to factor polynomials efficiently
Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Learning Objectives for This Lesson

By the end of this lesson, you should be able to:

  1. State the Remainder Theorem: when is divided by , the remainder equals
  2. Use the Remainder Theorem with synthetic division to evaluate polynomials efficiently
  3. State and apply the Factor Theorem: is a factor if and only if
  4. Test potential rational roots using the Factor Theorem
  5. Explain why the Remainder Theorem is true from the division equation
Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Recall: Division and Polynomial Evaluation

  • Division algorithm: (dividend = divisor × quotient + remainder)
  • Remainder: the constant left over — not the quotient
  • Evaluate : substitute into

Quick check: what is for ?

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

What Is the Remainder When You Divide?

Integer division: remainder

Check:

Polynomial division: divide by — what is the remainder?

Can you find it without doing the full division?

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Integer and Polynomial Division: Same Structure

Integer Polynomial
equation
divisor
quotient
remainder constant
Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Remainder Is Always a Constant Here

When is divided by (degree 1):

  • Remainder degree : so is a constant
  • Identity holds for every — pick
Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Long Division Confirms the Structure

Divide by :

Remainder = 7

Now evaluate directly:

Long division of x³+2x-5 by (x-2) showing quotient x²+2x+6 and remainder 7, with p(2)=7 verification

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Quick Check: Long Division Practice

Divide by :

  1. What is the quotient?
  2. What is the remainder?
  3. Verify: evaluate and confirm it equals your remainder.

Try it before moving on.

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

The Remainder Theorem: No Division Needed

Remainder Theorem: For any polynomial and any number :

The remainder when is divided by equals .

Shortcut: To find the remainder — just evaluate .

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

The Proof Walks Through One Step

The division equation is true for all :

Substitute — valid because the equation holds everywhere:

Therefore:

Proof equation with x = a substituted: each term labeled, (a-a) collapses to 0, r = p(a) revealed

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Remainder Theorem: First Worked Example

Find the remainder when is divided by .

By the Remainder Theorem: remainder

Remainder

(No long division needed.)

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Remainder Theorem Example Two: Sign Alert

Find the remainder when is divided by .

, so

Remainder

Divisor means , not .

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Remainder Theorem: Third Worked Example

Find the remainder when is divided by .

Remainder

Missing powers (like here) have coefficient 0.

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Find the Sign Error in This Solution

A student evaluates the remainder when is divided by :

"Remainder = p(3) = 27 − 15 + 1 = 13"

What is wrong? What should the student have done?

Identify the error and give the correct remainder.

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Practice: Apply the Remainder Theorem Now

Find the remainder when is divided by :

  1. What is ?
  2. Evaluate — that is the remainder.

No division needed.

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Factor Theorem: Zeros Equal Factors

Factor Theorem (corollary of Remainder Theorem):

is a factor

  • If: remainder exact division
  • Only-if:
Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Test Both Directions of the Factor Theorem

Direction 1: — is a factor?

Direction 2: Is a factor of ?

No.

Decide Direction 1 before advancing.

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Factor Theorem: Factoring a Cubic

Factor :

✓ → is a factor

Divide → quotient

Three-step factoring flow: test p(1)=0 then divide then factor quotient, with final factored form

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Factoring When Leading Coefficient Isn't One

Factor :

✓ → is a factor

Quotient:

Zeros:

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Rational Root Theorem: Finite Candidates

Rational zero : ,

For :

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

From Factor Theorem to Synthetic Division

Factor Theorem: confirms a factor exists.

Synthetic division: computes the quotient.

  • Divide out to reduce the degree
  • Final number always equals — built-in check
Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Synthetic Division: The Layout and Steps

Divide by , :

  • Write at left; coefficients across the top
  • Bring down → multiply by → add → repeat

Last number = remainder =

Synthetic division layout for 2x³-3x²+x-5 ÷ (x-2): labeled rows showing coefficients, products, running sums; last value = p(2)

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Synthetic Division: Walk Through the Steps

Divide by :

Quotient: , Remainder:

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Synthetic Division: When Remainder Is Zero

Remainder is a factor of

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Your Turn: Factor This Cubic Completely

  1. Find a zero using the Factor Theorem.
  2. Use synthetic division to get the quotient.
  3. Factor the quotient.

No hints — do the full procedure yourself.

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Two Zeros: Partial Factored Form

Suppose you test and find:

Without computing the full factorization: what do you know about the factored form of ?

Write the partial form. How many total factors does a cubic have?

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Three Common Errors to Watch For

⚠️ Wrong sign: , not

⚠️ Bottom row: last number = remainder; rest = quotient

⚠️ RRT isn't exhaustive: no rational roots ≠ no real roots

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Evaluation and Division Are Connected

Remainder Theorem: dividing by gives remainder

Factor Theorem: is a factor

Workflow: find zero → name factor → divide → factor quotient

⚠️ is the zero of the divisor — not the divisor itself

Grade 9 Algebra | HSA.APR.B.2
Remainder Theorem | Lesson 2 of 7: HSA.APR

Next: Zeros Reveal the Graph's Shape

You can now find all zeros of a polynomial using the Factor Theorem.

The next question: what does the graph do near each zero?

  • Cross the -axis, or bounce off it?

That depends on how many times each factor appears.

APR.B.3 — Graphing Polynomials from Zeros

Grade 9 Algebra | HSA.APR.B.2