Why IQR Is Better Than Range
- Range goes from 13 to 23 — nearly doubles when a 75" student is added
- IQR stays close to 4.5 — barely changes
- IQR is resistant to extreme values; range is not
Worked Example: Compute IQR Step by Step
Data (n = 7): 2, 4, 5, 7, 9, 10, 12
Step 1: Median = position 4 → 7
Step 2: Lower half: 2, 4, 5 → Q1 = 4
Step 3: Upper half: 9, 10, 12 → Q3 = 10
Your Turn: Compute the IQR
Data (n = 6): 3, 5, 5, 6, 7, 9
- Find the median
- Find Q1 and Q3
- Compute IQR
Try it, then advance for the answer.
IQR Worked Out: Splitting Even Data
- Median = (5 + 6) ÷ 2 = 5.5
- Lower half: 3, 5, 5 → Q1 = 5
- Upper half: 6, 7, 9 → Q3 = 7
- IQR = 7 − 5 = 2
Even n: split directly in half; no value excluded.
Why Signed Deviations Always Sum to Zero
Data: 4, 7, 5, 3, 6 — Mean = 5
| Value | Deviation |
|---|---|
| 4 | −1 |
| 7 | +2 |
| 5 | 0 |
| 3 | −2 |
| 6 | +1 |
| Sum | 0 |
Why We Need Absolute Values
- Signed deviations always sum to zero — their average is always 0
- Zero says nothing about how spread out data is
Fix: Take the absolute value of each deviation.
- Turns distances positive — cancellation stops
- The average is now meaningful distance from the mean
Computing MAD Step by Step
- Data: 4, 7, 5, 3, 6 (mean = 5); absolute deviations: 1, 2, 0, 2, 1
- Sum of absolute deviations = 6
units
MAD for the Heights Data
Heights (n = 25), mean = 58.2 in — same four steps:
- Subtract 58.2 from each value
- Take absolute values
- Sum → divide by 25
MAD ≈ 2.4 inches — a typical height is 2.4 in from the mean
Your Turn: Computing MAD from Scratch
Data (n = 3): 6, 8, 10 — Mean = 8
- Compute signed deviations
- Verify their sum = 0
- Take absolute values
- Compute MAD
Try it, then advance.
Predict: What Happens Without Absolute Value?
A student computes MAD for 6, 8, 10 but forgets the absolute value bars.
What answer do they get?
- A) MAD = 0
- B) MAD = 2
- C) Between 0 and 2
Commit to A, B, or C before advancing.
Skipping Absolute Value Always Gives Zero
Without absolute value: −2, 0, +2
Answer: A — MAD = 0
- Zero means "no spread" — clearly wrong
- Sign cancellation is always exact — by definition of the mean
- Absolute values are never optional
Describing Pattern and Striking Deviations
You now have IQR and MAD — next, describe the data qualitatively:
- Overall pattern — shape (symmetric / skewed), center, typical spread
- Striking deviations — values that stand clearly apart from the bulk
Identify outliers by inspection at grade 6 — "does it look separated?" is enough.
Heights Data: Pattern and Deviation
Overall pattern:
- Roughly symmetric, peak around 56–58 inches
- Most values within 4–5 inches of center
Striking deviation:
- 65 inches — ~3 inches above next-tallest (62, 63)
- Real data; on the upper edge of typical for the grade
Homework Hours Data: Pattern and Deviation
Data: 0, 0.5, 0.5, 1, 1, 1, 1, 1.5, 1.5, 2, 2, 6 (n=12)
Overall pattern:
- Right-skewed; peak around 1 hour; long right tail
Striking deviation:
- Value 6 — next highest is 2 (gap: 4 hours)
- Real data, but very unusual; may reflect a heavy assignment day
Context Determines What to Do With Outliers
| Context | Deviation means | Response |
|---|---|---|
| Height | Unusually tall/short person | Describe and include |
| Test scores | Student absent or no-show | Investigate, flag |
| Instrument | Recording error | Check, possibly correct |
Describe the deviation — never silently remove it.
Both Data Sets Described — Now Choose
| Heights | Homework Hours | |
|---|---|---|
| Shape | Roughly symmetric | Right-skewed |
| Mean | 58.2 in | 1.46 hr |
| Median | 57.0 in | 1.0 hr |
| IQR | 4.5 in | 1.0 hr |
| MAD | ≈ 2.4 in | large (pulled by 6) |
Which pair fits each data set — and why?
Shape Determines Which Measures to Report
These are heuristics — judgment, not formula. Always explain your choice.
Apply the Rule: Two Data Sets
Heights (symmetric):
- Mean 58.2 ≈ median 57 — use mean + MAD
Homework hours (right-skewed):
- Mean 1.46 pulled up by 6-hour value; median = 1.0
- Use median + IQR — resistant to the extreme
Context Layer: When to Use Mean Anyway
- Typical individual? → Median
- Total amount? → Mean (even with skewed data)
Homework hours: mean × 12 ≈ 17.5 hrs total; median × 12 = 12 hrs — not the actual total
Complete Summary: Heights Data (Symmetric)
"Heights of 25 sixth graders, in inches, tape measure. Roughly symmetric, peak 56–58. Mean = 58.2 in; MAD ≈ 2.4 in. Value of 65 sits slightly apart — upper edge of typical."
n ✓ attribute ✓ method ✓ shape ✓ center ✓ variation ✓ deviation ✓
Complete Summary: Homework Hours (Skewed)
"12 students, homework hours, nearest half-hour. Right-skewed — most 0.5–2 hrs, one reported 6. Median = 1 hr; IQR = 1 hr. The 6-hour value may reflect a heavy assignment day."
n ✓ attribute ✓ method ✓ shape ✓ center ✓ variation ✓ deviation ✓
Your Turn: Write a Full Summary
Bakery order costs (dollars), n = 10:
3, 5, 5, 6, 7, 8, 9, 10, 12, 35
- Compute median, Q1, Q3, IQR
- Describe shape and deviations
- Choose measures — give a reason
- Write the complete summary
No scaffolding — this is the real test.
Bakery Exit Task: Worked Answer
1. Median = $7.50; Q1 = $5; Q3 = $9.50; IQR = $4.50
2. Right-skewed; $35 far above next highest ($12)
3. Median + IQR — $35 distorts the mean
4. "10 bakery orders, dollars. Right-skewed — most $3–$12, one $35. Median $7.50; IQR $4.50. The $35 order may reflect a group purchase."
What You Have Learned Today
- Lead with n, attribute, units — required for any summary
- IQR = Q3 − Q1: middle 50%; resistant to extremes
- MAD: average |value − mean|; absolute value required
- Symmetric: mean + MAD; skewed: median + IQR
- IQR ≠ range; omit abs value: MAD = 0
Comparing Two Distributions in Grade Seven
- Grade 7: compare two distributions side by side
- Which class scored more consistently?
- Which neighborhood has the more typical commute?
The measures you choose here (7.SP.B.3) determine how you'll compare.