Why IQR Is Better Than Range
- Range goes from 13 to 23 — nearly doubles when a 75" student is added
- IQR stays close to 4.5 — barely changes
- IQR is resistant to extreme values; range is not
Worked Example: Compute IQR Step by Step
Data (n = 7): 2, 4, 5, 7, 9, 10, 12
Step 1: Median = position 4 → 7
Step 2: Lower half: 2, 4, 5 → Q1 = 4
Step 3: Upper half: 9, 10, 12 → Q3 = 10
Your Turn: Compute the IQR
Data (n = 6): 3, 5, 5, 6, 7, 9
- Find the median
- Find Q1 and Q3
- Compute IQR
Try it, then advance for the answer.
IQR Worked Out: Splitting Even Data
- Median = (5 + 6) ÷ 2 = 5.5
- Lower half: 3, 5, 5 → Q1 = 5
- Upper half: 6, 7, 9 → Q3 = 7
- IQR = 7 − 5 = 2
Even n: split directly in half; no value excluded.
Why Signed Deviations Always Sum to Zero
Data: 4, 7, 5, 3, 6 — Mean = 5
| Value | Deviation |
|---|---|
| 4 | −1 |
| 7 | +2 |
| 5 | 0 |
| 3 | −2 |
| 6 | +1 |
| Sum | 0 |
Why We Need Absolute Values
- Signed deviations always sum to zero — their average is always 0
- Zero says nothing about how spread out data is
Fix: Take the absolute value of each deviation.
- Turns distances positive — cancellation stops
- The average is now meaningful distance from the mean
Computing MAD Step by Step
- Data: 4, 7, 5, 3, 6 (mean = 5); absolute deviations: 1, 2, 0, 2, 1
- Sum of absolute deviations = 6
units
MAD for the Heights Data
Heights (n = 25), mean = 58.2 in — same four steps:
- Subtract 58.2 from each value
- Take absolute values
- Sum → divide by 25
MAD ≈ 2.4 inches — a typical height is 2.4 in from the mean
Your Turn: Computing MAD from Scratch
Data (n = 3): 6, 8, 10 — Mean = 8
- Compute signed deviations
- Verify their sum = 0
- Take absolute values
- Compute MAD
Try it, then advance.
Predict: What Happens Without Absolute Value?
A student computes MAD for 6, 8, 10 but forgets the absolute value bars.
What answer do they get?
- A) MAD = 0
- B) MAD = 2
- C) Between 0 and 2
Commit to A, B, or C before advancing.
Skipping Absolute Value Always Gives Zero
Without absolute value: −2, 0, +2
Answer: A — MAD = 0
- Zero means "no spread" — clearly wrong
- Sign cancellation is always exact — by definition of the mean
- Absolute values are never optional
Describing Pattern and Striking Deviations
You now have IQR and MAD — next, describe the data qualitatively:
- Overall pattern — shape (symmetric / skewed), center, typical spread
- Striking deviations — values that stand clearly apart from the bulk
Identify outliers by inspection at grade 6 — "does it look separated?" is enough.
Heights Data: Pattern and Deviation
Overall pattern:
- Roughly symmetric, peak around 56–58 inches
- Most values within 4–5 inches of center
Striking deviation:
- 65 inches — ~3 inches above next-tallest (62, 63)
- Real data; on the upper edge of typical for the grade
Homework Hours Data: Pattern and Deviation
Data: 0, 0.5, 0.5, 1, 1, 1, 1, 1.5, 1.5, 2, 2, 6 (n=12)
Overall pattern:
- Right-skewed; peak around 1 hour; long right tail
Striking deviation:
- Value 6 — next highest is 2 (gap: 4 hours)
- Real data, but very unusual; may reflect a heavy assignment day
Context Determines What to Do With Outliers
| Context | Deviation means | Response |
|---|---|---|
| Height | Unusually tall/short person | Describe and include |
| Test scores | Student absent or no-show | Investigate, flag |
| Instrument | Recording error | Check, possibly correct |
Describe the deviation — never silently remove it.
Both Data Sets Described — Now Choose
| Heights | Homework Hours | |
|---|---|---|
| Shape | Roughly symmetric | Right-skewed |
| Mean | 58.2 in | 1.46 hr |
| Median | 57.0 in | 1.0 hr |
| IQR | 4.5 in | 1.0 hr |
| MAD | ≈ 2.4 in | large (pulled by 6) |
Which pair fits each data set — and why?
Shape Determines Which Measures to Report
These are heuristics — judgment, not formula. Always explain your choice.
Apply the Rule: Two Data Sets
Heights (symmetric):
- Mean 58.2 ≈ median 57 — use mean + MAD
Homework hours (right-skewed):
- Mean 1.46 pulled up by 6-hour value; median = 1.0
- Use median + IQR — resistant to the extreme
Context Layer: When to Use Mean Anyway
- Typical individual? → Median
- Total amount? → Mean (even with skewed data)
Homework hours: mean × 12 ≈ 17.5 hrs total; median × 12 = 12 hrs — not the actual total
Complete Summary: Heights Data (Symmetric)
"Heights of 25 sixth graders, in inches, tape measure. Roughly symmetric, peak 56–58. Mean = 58.2 in; MAD ≈ 2.4 in. Value of 65 sits slightly apart — upper edge of typical."
n ✓ attribute ✓ method ✓ shape ✓ center ✓ variation ✓ deviation ✓
Complete Summary: Homework Hours (Skewed)
"12 students, homework hours, nearest half-hour. Right-skewed — most 0.5–2 hrs, one reported 6. Median = 1 hr; IQR = 1 hr. The 6-hour value may reflect a heavy assignment day."
n ✓ attribute ✓ method ✓ shape ✓ center ✓ variation ✓ deviation ✓
Your Turn: Write a Full Summary
Bakery order costs (dollars), n = 10:
3, 5, 5, 6, 7, 8, 9, 10, 12, 35
- Compute median, Q1, Q3, IQR
- Describe shape and deviations
- Choose measures — give a reason
- Write the complete summary
No scaffolding — this is the real test.
Bakery Exit Task: Worked Answer
1. Median = $7.50; Q1 = $5; Q3 = $9.50; IQR = $4.50
2. Right-skewed; $35 far above next highest ($12)
3. Median + IQR — $35 distorts the mean
4. "10 bakery orders, dollars. Right-skewed — most $3–$12, one $35. Median $7.50; IQR $4.50. The $35 order may reflect a group purchase."
What You Have Learned Today
- Lead with n, attribute, units — required for any summary
- IQR = Q3 − Q1: middle 50%; resistant to extremes
- MAD: average |value − mean|; absolute value required
- Symmetric: mean + MAD; skewed: median + IQR
- IQR ≠ range; omit abs value: MAD = 0
Comparing Two Distributions in Grade Seven
- Grade 7: compare two distributions side by side
- Which class scored more consistently?
- Which neighborhood has the more typical commute?
The measures you choose here (7.SP.B.3) determine how you'll compare.
Click to begin the narrated lesson
Summarize numerical data sets in relation to their context